在线等:(x^2+x+1)^2+(x^2+x+1)+1怎么算?

设y=x^2+x+1 则有原式＝y^2+y=1=(y+1）^2-y
代入y=x^2+x+1
则原式＝（x^2+x+1＋1)^2-(x^2+x+1)
=(x+2)^2*(x-1)^2-(x-1)^2-3x
=(x-1)^2(x^2+4x+3)-3x
=(x-1)^2(x+3)(x+1)-3x
=(x^2+2x-3)(x^2-1)-3x
=x^4-x^2+2X^3-2x-3x^2+3-3x
=x^4+2x^3-4x^2-5x+3

跟楼上一样，先y=x^2+x+1，
然后原式=y^2+y+1
=(y-1)^2+3y
会好算点，后面自己画简